Answer:
the percent error in the student's measurement is 4.65%.
Explanation:
The percent error can be calculated using the formula:
| (measured value - actual value) / actual value | * 100%
In this case, the measured value is 2.7 grams and the actual value is 2.58 grams. Substituting these values into the formula, we get:
| (2.7 - 2.58) / 2.58 | * 100% = 4.65%
Rounding this to the nearest hundredth of a percent, we get a percent error of 4.65%.
Therefore, the percent error in the student's measurement is 4.65%.