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Determine the concentration of 0.0430 grams of Pb+2 ion in 0.100 liters of solution. Please use significant figures.

User Leko
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To determine the concentration of Pb+2 ion in the given solution, we need to divide the amount of Pb+2 ion by the volume of the solution:

Concentration = amount of Pb+2 ion / volume of solution

First, we need to convert the given mass of Pb+2 ion to moles, using the molar mass of Pb+2:

molar mass of Pb+2 = 207.2 g/mol

moles of Pb+2 = 0.0430 g / 207.2 g/mol = 0.0002076 mol

Next, we can plug in the values into the formula:

Concentration = 0.0002076 mol / 0.100 L = 0.00208 M

To follow significant figure rules, the concentration should be rounded to 3 significant figures, since the least precise value (0.100 L) has 1 significant figure:

Concentration = 0.00208 M (rounded to 3 significant figures)
User Czarek Tomczak
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