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15 votes
I need help with part a and B on number three

I need help with part a and B on number three-example-1
User Jitin
by
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1 Answer

15 votes
15 votes

Answer:

a. 2.64 * 10^8 radians

b. 4.20 * 10^ 7 revolutions

Explanation:

First, let us convert miles to inches.


60,000\text{miles}=3.8\cdot10^9in

Now, how many radians of the tire are there in 60,000 miles?

The answer is N in the following equation.


2\pi((28.8)/(2))N=3.8\cdot10^p

Now, solving for 2Pi*N gives


2\pi N=(2.8\cdot10^9)/(28.8/2)

Which simplifies to give


\boxed{2\pi N=2.64\cdot10^8}

Part B.

Note that in the above equation, N is the number of Revolutions. Solving for N gives


N=(2.64\cdot10^8)/(2\pi)


\boxed{N=4.20\cdot10^7}

which is our answer!

User Siham
by
2.8k points