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Find m angle BCA. please help if you can!!

Find m angle BCA. please help if you can!!-example-1

2 Answers

3 votes

Answer:

  • m∠BCA = 57°

Explanation:


\tt 10x+37+9x+1+5x+12=360^o

Add like terms:-


\tt 10x+9x+5x=360^o+37^o-1^o-12^o


\tt 10x+9x+5x=\bf 24x


\tt 360+37-1-12=\bf 384


\tt 24x=384

Divide both sides by 24:-


\tt \cfrac{24x}{24}=\cfrac{384}{24}


\tt x=16^o

Now, let's find m∠BCA:-

m∠BCA = 180-(10x-37)


\tt 180-(10(16)-37)


\tt 180-123


\tt 57^o

Therefore, m∠BCA = 57°.

________________________

Hope this helps!

User George Borunov
by
7.7k points
2 votes

Answer:

  • m∠BCA = 57°

-------------------------------

Sum of exterior angles measures is 360°.

Set up the following equation and solve for x:

  • 9x + 1 + 5x + 12 + 10x - 37 = 360
  • 24x - 24 = 360
  • 24x = 384
  • x = 384/24
  • x = 16

Find exterior angle measure at vertex C:

  • 10*16 - 37 = 160 - 37 = 123°

We know interior and exterior angles on the same vertex form a linear pair.

Find interior angle at vertex C, the ∠BCA:

  • m∠BCA = 180° - 123° = 57°
User Chinese Cat
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8.0k points