Question

15b^2 + 4b - 4 =0 factorize

Answer 1

A Quadratic equation can have the form:

`ax^2+bx+c=0`

Where "a" is the Leading coefficient.

In this case, you have the following Quadratic equation:

`15b^2+4b-4=0`

You can rewrite it as following:

`15x^2+4x-4=0`

The steps to factorize it are shown below:

1. Use the Quadratic formula:

`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

2. You can see that:

`\begin{gathered} a=15 \\ b=4 \\ c=-4 \end{gathered}`

3. Substitute values into the Quadratic formula and evaluate:

`\begin{gathered} x=\frac{-4\pm\sqrt[]{4^2-4(15)(-4)}}{2(15)} \\ \\ x_1=(2)/(5) \\ \\ x_2=-(2)/(3) \end{gathered}`

4. Substituting the variable "x" by the variable "b", you can write it in the following factor form:

`15(b-(2)/(5))(b+(2)/(3))=0`

The answer is:

`15(b-(2)/(5))(b+(2)/(3))=0`