Question

Prove that for all real numbers x and y, if x > 0 and y < 0, then x · y < 0.

Answer 1

Answer: This is correct

Step-by-step explanation: if x is > 0 then that means it is a positive number and y < 0 means it is less than 0 making it a negative number, and a negative times a positive is a negative and a negative is smaller than 0