The correct answers are A, C, and D.
We have f(x) = 3-2x.
A. f^-1(1) = x, where f(x) = 1
=> 3 - 2x = 1
=> x = 1
Therefore, f^-1(1) = 1. This statement is true.
B. f^1(-1) = y, where f(y) = -1
=> 3 - 2y = -1
=> y = 2
Therefore, f^1(-1) = 2. This statement is false.
C. f^-1(2) = x, where f(x) = 2
=> 3 - 2x = 2
=> x = 1/2
Therefore, f^-1(2) = 1/2. This statement is true.
D. (f o f^-1)(-2) = -2
(f o f^-1)(-2) means apply f^-1 to -2 and then apply f to the result.
Let y = f^-1(-2)
=> f(y) = -2
=> 3 - 2y = -2
=> y = 5/2
=> f(5/2) = 3 - 2(5/2) = -2
Therefore, (f o f^-1)(-2) = -2. This statement is true.