Question

Assume that the brakes in your car create a constant deceleration of 3.9 m/s2

regardless of how fast you are driving.

Calculate the stopping distance for initial speed of 15 m/s

Answer 1

Answer: the stopping distance for an initial speed of 15 m/s with a constant deceleration of 3.9 m/s² is approximately 57.7 meters.

Step-by-step explanation:

To calculate the stopping distance, we need to use the following equation of motion:

v² = u² + 2as

where:

v is the final velocity (in this case, it is 0 because the car stops)

u is the initial velocity (15 m/s)

a is the deceleration (-3.9 m/s²)

s is the stopping distance (what we want to find)

Substituting the given values in the equation, we get:

0² = 15² + 2(-3.9)s

Simplifying and solving for s, we get:

s = (15²) / (2 × 3.9) ≈ 57.7 meters