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Nicole has two bags of coins. The first bag contains 5 silver dollars, 4 quarters, and 6 dimes. The second bag contains 2 silver dollars, 3 quarters, and 2 dimes. Nicole is going to let her little brother, Jacob, randomly select and keep 1 coin from each bag. What is the probability that Jacob will choose a silver dollar from each bag?

1 Answer

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First, we need to find the probability of Jacob choosing a silver dollar from the first bag and a silver dollar from the second bag.

The probability of choosing a silver dollar from the first bag is 5/15 = 1/3 since there are 5 silver dollars out of a total of 15 coins in the bag.

The probability of choosing a silver dollar from the second bag is 2/7 since there are 2 silver dollars out of a total of 7 coins in the bag.

To find the probability of both events happening (Jacob choosing a silver dollar from each bag), we multiply the probabilities:

(1/3) x (2/7) = 2/21

Therefore, the probability that Jacob will choose a silver dollar from each bag is 2/21.

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