Question

The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0

Answer 1

The three equations that can be used to solve for y, the length of the room, are:

1. y(y + 5) = 750

2. y^2 – 5y = 750

3. (y + 25)(y – 30) = 0

Step-by-step explanation:

Let's assume that the length of the room is y and the width of the room is y - 5.

We know that the area of the room is the product of its length and width, so we can write an equation:

y(y - 5) = 750

Simplifying this equation, we get:

y^2 - 5y - 750 = 0

Now we can solve this quadratic equation using the quadratic formula or factoring method. By factoring, we can get equation 3. By using the quadratic formula, we can get equation 2. Equation 1 is just another form of equation 2. Therefore, options 1, 2, and 3 can be used to solve for y. Option 4 is not a valid equation as it doesn't represent the area of the room.