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What would be the mass of 1.98 * 10^(28) molecules of H2O

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2 votes

Answer:

The molar mass of H2O is approximately 18.015 g/mol.

To calculate the mass of 1.98 * 10^28 molecules of H2O, we need to first calculate the number of moles of H2O represented by that many molecules:

1.98 * 10^28 molecules H2O / 6.022 * 10^23 molecules/mol = 32.9 mol H2O

Next, we can use the molar mass of H2O to convert from moles to grams:

32.9 mol H2O * 18.015 g/mol = 591.6 g

Therefore, the mass of 1.98 * 10^28 molecules of H2O is approximately 591.6 grams

User Humilton
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5 votes
Answer: The mass of water would be 5.918 x 10 to the power of 5 g
Step-by-step explanation:
According to the mole concept:
1 mole of a compound contains number of molecules which determines the molar mass of that compound.
Mass of water for 1 mole is 18 grams.
User Daniel Kullmann
by
9.0k points

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