Answer:
To calculate the enthalpy of vaporization for the phase change from gaseous methanol to liquid methanol:
1. Determine the standard enthalpy of formation of both states: CH3OH (g) is -201.8 kJ/mol and CH3OH (l) is -238.7 kJ/mol.
2. Subtract the standard enthalpy of formation of the liquid state from the standard enthalpy of formation of the gaseous state: -201.8 kJ/mol -(-238.7 kJ/mol) = 36.9 kJ/mol.
3. The enthalpy of vaporization for the phase change from gaseous methanol to liquid methanol is 36.9 kJ/mol.