Answer:
If a physics student skis down a slope with a constant acceleration of 2.0m/s^2 for 15 seconds, we can use the following kinematic equation to determine the distance traveled by the student:
$d = v_0 t + \frac{1}{2}at^2$
where d is the distance traveled, $v_0$ is the initial velocity (which we assume to be zero since the student starts from rest), t is the time, and a is the acceleration.
Substituting the given values, we get:
$d = (0) (15) + \frac{1}{2} (2.0\text{ m/s}^2) (15)^2 = 225\text{ m}$
Therefore, the distance traveled by the physics student is 225 meters.