If you put x=1 into your function, you'd have
f(1) = -3(1) + 5
= -3 + 5
= 2
This shows that Table A is not correct.
If you put x=2 into your function, you'd have
f(2) = -3(2) + 5
= -6 + 5
= -1
This shows that Table B is not correct.
That leaves Table C.