Question

In the diagram below of A ADB, mZBDA = 90, AD=52/2, and AB=2V15. B A А D What is the length of BD? Your answer

Answer 1

Applying the Pythagorean Theorem

we have

AB^2=AD^2+BD^2

substitute given values

`(2\sqrt[\square]{15})^2=(5\sqrt[\square]{2})^2+BD^2`

solve for BD

`\begin{gathered} 60=50+BD^2 \\ BD^2=60-50 \\ BD^2=10 \\ BD=\sqrt[\square]{10} \end{gathered}`