Question

Please help need to answer this and i am bad at math

Answer 1

Answer: C

Explanation:

If f(x) = 0, the non-monic quadratic would be 2x^2-3x-5 = 0. After that, factor 2x^2-3x-5, which becomes (x+1)(2x-5), so x+1=0 and 2x-5=0.

x+1=0 -- x=-1

2x-5=0 -- 2x=5 -- x=5/2

Therefore, the answer would be C.

Answer 2

C

Explanation:

f(x) = 2x² - 3x - 5

to find the zeros , set f(x) = 0 , that is

2x² - 3x - 5 = 0 ← in standard form

consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 2 × - 5 = - 10 and sum = - 3

the factors are + 2 and - 5

use these factors to split the x- term

2x² + 2x - 5x - 5 = 0 ( factor the first/second and third/fourth terms )

2x(x + 1) - 5(x + 1) = 0 ← factor out (x + 1) from each term

(x + 1)(2x - 5) = 0 ← in factored form

equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

2x - 5 = 0 ( add 5 to both sides )

2x = 5 ( divide both sides by 2 )

x =
`(5)/(2)`

then

zeros are - 1 and
`(5)/(2)` because f(x) = (x + 1)(2x - 5)