177k views
3 votes
Find the resistance that exist in a circuit that has a voltage of 85000mu and a current of 9400MA​

User Mattexx
by
8.3k points

1 Answer

3 votes

Answer:

the resistance in the circuit is approximately 9.04 microohms.

Step-by-step explanation:

The voltage and current in the circuit are given in different units, so we need to convert them to a common unit before calculating the resistance.

The voltage is given as 85000 mu, which is short for 85,000 microvolts. To convert microvolts to volts, we need to divide by one million:

85000 mu = 85,000 / 1,000,000 V = 0.085 V

The current is given as 9400 MA, which is short for 9,400,000 amperes. To convert amperes to milliamperes, we need to multiply by one thousand:

9400 MA = 9,400,000 mA

Now that we have both voltage and current in the same units, we can use Ohm's law to calculate the resistance:

Resistance (R) = Voltage (V) / Current (I)

R = 0.085 V / 9,400,000 mA

R = 0.085 V / 9,400 A

R = 9.04 microohms

Therefore, the resistance in the circuit is approximately 9.04 microohms.

User RiccardoC
by
7.0k points