Question

alex attaches a diagonal brace to a rectangular-shaped picture frame. if the dimensions of the frame were 33 inches and 44 inches, what is the length of the brace?

Answer 1

The length of the diagonal brace is 55 inches.

Explanation:

We can use the Pythagorean theorem to find the length of the diagonal brace. The Pythagorean theorem states that for a right triangle, the square of the length of the hypotenuse (the diagonal brace in this case) is equal to the sum of the courts of the sizes of the other two sides (the two sides of the rectangular-shaped picture frame).

So, in this case, the length of one side of the rectangular-shaped picture frame is 33 inches, and the size of the other is 44 inches. Therefore, the size of the diagonal brace (h) can be calculated as follows:

h^2 = 33^2 + 44^2

h^2 = 1089 + 1936

h^2 = 3025

h = √3025

h = 55

Answer 2

Explanation:

We can use the Pythagorean theorem to find the length of the diagonal brace. The Pythagorean theorem states that for a right triangle, the square of the length of the hypotenuse (the diagonal brace in this case) is equal to the sum of the squares of the lengths of the other two sides (the two sides of the rectangular-shaped picture frame).

So, in this case, the length of one side of the rectangular-shaped picture frame is 33 inches and the length of the other side is 44 inches. Therefore, the length of the diagonal brace (h) can be calculated as follows:

h^2 = 33^2 + 44^2

h^2 = 1089 + 1936

h^2 = 3025

h = √3025

h = 55

Therefore, the length of the diagonal brace is 55 inches.