Answer:
6.44 mol/kg
Step-by-step explanation:
Calculate the molality for 22.0g fecl2 in 27.0g h20
Molality (m) is defined as the number of moles of solute per kilogram of solvent.
To calculate the molality of a solution containing 22.0 g of FeCl2 in 27.0 g of H2O, we first need to convert the given masses of solute and solvent into their respective amounts in moles.
The molar mass of FeCl2 can be calculated as follows:
FeCl2 = 1 x 55.85 + 2 x 35.45 = 126.75 g/mol
The number of moles of FeCl2 is:
nFeCl2 = mass / molar mass = 22.0 g / 126.75 g/mol = 0.1736 mol
The molar mass of H2O is:
H2O = 2 x 1.01 + 16.00 = 18.02 g/mol
The number of moles of H2O is:
nH2O = mass / molar mass = 27.0 g / 18.02 g/mol = 1.499 mol
Now that we have the amounts of solute and solvent in moles, we can calculate the molality using the following formula:
molality = moles of solute / mass of solvent in kg
To express the mass of solvent in kilograms, we divide by 1000:
mass of solvent in kg = 27.0 g / 1000 = 0.027 kg
Now we can calculate the molality:
molality = 0.1736 mol / 0.027 kg = 6.44 mol/kg
Therefore, the molality of the solution containing 22.0 g of FeCl2 in 27.0 g of H2O is 6.44 mol/kg.