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A runner achieves a velocity of 11.1 m/s, 9 sec after he begins. What is his acceleration? What distance did he cover?

User Sola Yang
by
8.5k points

2 Answers

5 votes

Answer: Acceleration of the runner =1.23 m/s²

The distance covered by the runner will be 99.9 m

Explanation: Given,

Velocity=11.1 m/s²

Time= 9 seconds

Acceleration=?

Acceleration = Velocity/Time

Acceleration = 11.1 / 9

Acceleration = 1.23 m/s²

The distance covered by the runner= 11.1 m/s² × 9 seconds

The distance covered by the runner= 99.9 m

User RVid
by
7.7k points
1 vote

Answer:

Explanation: velocity = distance/time

velocity (v) = 11.1m/s

time =9 sec

distance =velocity x time

distance = 11.1 x 9 =99.9m

User Eric Steen
by
7.8k points