Question

How many grams of C are required to react with 56.8 g of Fe2O3?Fe2O3(s)+3C(s)→2Fe(s)+3CO(g)

Answer 1

`Fe_2O_(3(s))+3C_((s))\rightarrow2Fe_((s))+3CO_g`

Firstly we have to convert the mass of the Fe2O3 to moles. We do this using the following equation:

`\begin{gathered} _nFe_2O_(3(g))=\frac{mass}{molar\text{ }mass} \\ _nFe_2O_(3(g))=(56.8g)/(159.7gmol^(-1)) \\ _nFe_2O_(3(g))=0.36mol \end{gathered}`

Based on the stichiometric ratio 1 mole of Fe2O3 reacts with 3 moles of carbon. Therefore 0.36 moles of Fe2O3 would react with x moles of carbon. We can determine x:

`\begin{gathered} _nx=3*0.36mol \\ _nx=1.08mole \end{gathered}`

Now that we have found the moles of carbon reacted, we will now convert this moles to mass:

`\begin{gathered} mass\text{ }C=moles* molar\text{ }mass \\ mass\text{ }C=1.08\text{ }mol*12.01\text{ }gmol^(-1) \\ mass\text{ }C=12.97g \end{gathered}`

Mass of carbon required to react with 56.8g of Fe2O3 is 12.97g or 13.0g.