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Megan had $5496 more than Jolene at first. Then their mother gave Jolene another $264 and Megan $856. Megan has 3 times as much money as Jolene in the end. (a) How much did Jolene have at first? (b) How much did Megan have at first?​

User Josephkibe
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Answer:

Explanation:

Let's use the variable "J" to represent Jolene's initial amount of money.

According to the problem, Megan had $5496 more than Jolene at first, so Megan's initial amount of money can be represented as J + $5496.

After their mother gave Jolene another $264, Jolene's new amount of money is J + $264.

After their mother gave Megan $856, Megan's new amount of money is J + $5496 + $856, which simplifies to J + $6352.

The problem also tells us that Megan has 3 times as much money as Jolene in the end, so we can write the equation:

J + $6352 = 3(J + $264)

Simplifying this equation, we get:

J + $6352 = 3J + $792

Subtracting J from both sides, we get:

$6352 = 2J + $792

Subtracting $792 from both sides, we get:

$5560 = 2J

Dividing both sides by 2, we get:

J = $2780

So Jolene had $2780 at first.

To find out how much Megan had at first, we can substitute J = $2780 into the equation we used earlier:

Megan's initial amount of money = J + $5496

Megan's initial amount of money = $2780 + $5496

Megan's initial amount of money = $8276

Therefore, Megan had $8276 at first.

User Iscle
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