Question

How do you Solve (d−5)^2=0.

Answer 1

d = 5

Explanation:

(d-5)² = 0

Using the algebraic identity (a-b)² = a² + b² - 2(a)(b)

d² + 25 - 10d = 0

d² - 10d + 25 = 0

d² - 5d - 5d + 25 = 0

d(d-5) -5(d-5) = 0

(d-5)(d-5)

d = 5