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3 votes
(cscx + 1)(cscx - 1)/ csc² x

1 Answer

3 votes

Answer:

cos²x

Explanation:

using the identity

cscx =
(1)/(sinx) and 1 - sin²x = cos²x

then


((cscx+1)(cscx-1))/(csc^2x) ← expand numerator using FOIL

=
(csc^2x-1)/((1)/(sin^2x) )

= (
(1)/(sin^2x) - 1 ) × sin²x

= sin²x(
(1)/(sin^2x) - 1) ← distribute parenthesis

= 1 - sin²x

= cos²x

User Haansi
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