Question

Julie and her husband on a coffee shop they experimented with mixing a city roast Colombia coffee that cost $7.80 per pound with French roast Columbian coffee that cost $8.10 per pound. How many pounds of each type of coffee should they buy ?

Answer 1

Explanation:

There are a couple of pieces of information missing in the problem statement, specifically what is the desired price per pound for the mixture, and how much of the mixture is needed in total. We will assume that Julie and her husband want to create a blend that costs $8.00 per pound, and that they want to make a total of 5 pounds of the blend.

Let x be the number of pounds of city roast Colombia coffee they should buy, and y be the number of pounds of French roast Columbian coffee they should buy.

We can set up two equations based on the information given:

x + y = 5 (since they want to make a total of 5 pounds of the blend)

7.8x + 8.1y = 40 (since the total cost of the blend should be $40, based on the desired price of $8.00 per pound)

We can solve this system of equations by substitution or elimination. Here, we will use substitution.

From the first equation, we have y = 5 - x. Substituting this into the second equation, we get:

7.8x + 8.1(5 - x) = 40

7.8x + 40.5 - 8.1x = 40

-0.3x = -0.5

x = 5/3

So they should buy 5/3 pounds of city roast Colombia coffee, and 5 - 5/3 = 10/3 pounds of French roast Columbian coffee.