Answer:
Explanation:
Let's call the speed of the jet in still air "j" and the speed of the wind "w". Then, we can set up the following system of equations:
j + w = 1124/4 = 281 (with the tailwind)
j - w = 956/4 = 239 (against the headwind)
We can solve this system using elimination. Adding the two equations eliminates w:
2j = 520
j = 260
Substituting j = 260 into one of the equations, we can solve for w:
260 + w = 281
w = 21
Therefore, the speed of the jet in still air is 260 mph and the speed of the wind is 21 mph.