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Consider the function f(x)=sqrt x-4+9 for the domain [4, infinity).
Find f^-1(x), where f^-1 is the inverse of f.
Also state the domain of f^-1 in interval notation.

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Answer: To find the inverse function of f(x), we need to solve for x in terms of f(x). We start by writing:

y = f(x) = sqrt(x - 4) + 9

We then swap x and y and solve for y:

x = sqrt(y - 4) + 9

x - 9 = sqrt(y - 4)

(x - 9)^2 = y - 4

y = (x - 9)^2 + 4

So the inverse of f(x) is f^(-1)(x) = (x - 9)^2 + 4.

To find the domain of f^(-1)(x), we need to consider the range of f(x), which is [5, infinity). Since the inverse function swaps the roles of x and y, the domain of f^(-1)(x) is [5, infinity). So in interval notation, the domain of f^(-1)(x) is [5, infinity).

Explanation:

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