Question

I need help with this answer as well can someone help me quickly please?

Answer 1

Explanation:

Let's use a system of equations to solve for the cost of each package. Let c be the cost of one package of coffee and t be the cost of one package of tea. Then we have:

Yesterday's sales: 11c + 14t = 166

Two days ago sales: 30c + 30t = 420

We can simplify the second equation by dividing both sides by 30:

c + t = 14

Now we can use substitution to solve for one of the variables. Let's solve for c by subtracting t from both sides of the simplified equation:

c = 14 - t

Substituting this expression for c into the first equation, we get:

11(14 - t) + 14t = 166

Expanding and simplifying, we get:

154 - 11t + 14t = 166

3t = 12

t = 4

So tea costs $4 per package. Substituting this value back into the simplified equation, we get:

c + 4 = 14

c = 10

Therefore, coffee costs $10 per package.

Answer 2

coffee costs $10

tea costs $4

Explanation:

c = cost of package of coffee

t = cost of package of tea

11c + 14t = 166

30c + 30t = 420 factor out the 30 and rewrite this equation

30(c + t) = 420 solve for c, then substitute it into the 1st equation

c + t = 420/30 = 14

c = 14 - t

11(14 - t) + 14t = 166 now solve for t

154 - 11t + 14t = 166

3t = 166 - 154 = 12

t = 12/3 = 4 plug this into the 2nd equation and solve for c

30c + 30(4) = 420

30c = 420 - 120

c = 300/30 = 10