Question

Let 0° < α < 90°
Given: sin α =5/13
Find: cos α and tan α

Answer 1

Explanation:

`cos\alpha =\sqrt{1-sin^(2) \alpha } =\sqrt{1-((5)/(13))^(2) } =\sqrt{(144)/(169) }`

=
`(12)/(13)`

`tan\alpha =(sin\alpha )/(cos\alpha ) =((5)/(13) )/((12)/(13) ) = (5)/(12)`