Question

For a moving object, the force acting on the object varies directly with the objects acceleration. When a force of 40 N acts on a certain object, the acceleration of the object is 4 m/s^2. If the acceleration of the object becomes 9 m/s^2, what is the score?

Answer 1

Explanation:

We can use the proportionality relationship between force and acceleration, which is given as:

force = constant × acceleration

Let's call the constant of proportionality k. Then we can write:

40 N = k × 4 m/s^2

Solving for k, we get:

k = 40 N / 4 m/s^2 = 10 Ns^2/m

Now we can use this value of k to find the force required for an acceleration of 9 m/s^2:

force = k × acceleration = 10 Ns^2/m × 9 m/s^2 = 90 N

Therefore, the force required for an acceleration of 9 m/s^2 is 90 N.