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72.02%Mn, 27.98% O empirical formula

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Answer:

Below

Step-by-step explanation:

From periodic table :

Mn = 54.938 and O =15.999 gm/mole

Take the percentages of each and divide by the gm/ mole of each:

Mn 72.02 / 54.938 = 1.31

O 27.98/15.999 = 1.74 divide these numbers by the smallest ( 1.31)

to get ratio: Mn = 1 O = .75 now get whole numbers (multiply by 4 )

Mn = 4 O = 3

Mn4 O3

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