Question

If 2 distinct numbers are chosen from the set below at random, what is the probabilityt that their sum will be greater than 100?

( 1, 5, 10, 100 )

Answer 1

Answer:0.50

Explanation:

{1 , 5 , 10 , 100)

Two numbers can be chosen from the above set of four numbers in 4C2 ways.

4C2 = 4!/(2!*2!) = (4*3*2!)/)2*2!) = 12/2 = 6

Two numbers can be chosen from the above set of four numbers in 6 ways.

The pair of numbers which give a sum greater than 100 is (1,100) , (5,100) , (10,100).

3 pairs out of 6 total pairs will give a sum greater than 100.

P(sum > 100) = 3/6 = 1/2 = 0.50

P(sum > 100) = 0.50

0.50