207k views
4 votes
A boy is whirling a rock attached to a string overhead in a horizontal circle with a radius of 1m. The rock has a tangential velocity of 12.56 m/s.

What is the centripetal acceleration of of the rock? (Please just plug in the number. No units & Round to the Hundreds place 0.00)

User Lafexlos
by
7.6k points

1 Answer

3 votes

Answer:

The centripetal acceleration of the rock can be calculated using the formula:

a = v^2 / r

where v is the tangential velocity and r is the radius of the circle.

Substituting the given values, we get:

a = (12.56 m/s)^2 / 1m = 157.93 m/s^2

Rounding to the hundreds place, the centripetal acceleration of the rock is approximately 157.93 m/s^2.

User Fred Finkle
by
7.4k points