Question

2KClO3 Right arrow. 2KCl + 3O2

How many moles of oxygen are produced when 2 mol of potassium chlorate (KClO3) decompose?
1
2
3
6

Answer 1

3 moles

Step-by-step explanation:

The balanced chemical equation for the decomposition of potassium chlorate is:

2KClO3 → 2KCl + 3O2

This means that for every 2 moles of KClO3 that decompose, 3 moles of O2 are produced. We are given that 2 moles of KClO3 decompose, so we can use the stoichiometry of the balanced equation to determine the amount of O2 produced.

2 moles KClO3 × (3 moles O2 / 2 moles KClO3) = 3 moles O2

Therefore, 3 moles of O2 are produced when 2 moles of KClO3 decompose.