Question

A car dealership decides to select a month at random for its annual sale find the probability that it will be July or October. Show all your work.

Answer 1

1/6

Step-by-step explanation:

The total number of months in a year = 12

`\begin{gathered} P(\text{July)}=(1)/(12) \\ P(\text{October)}=(1)/(12) \end{gathered}`

Therefore, the probability that it will be July or October:

`\begin{gathered} P(\text{July or October)=}P(\text{July)}+P(\text{October)} \\ =(1)/(12)+(1)/(12) \\ =(2)/(12) \\ =(1)/(6) \end{gathered}`

The required probability is 1/6.

Note:

• Use addition for OR

,

• Use multiplication for AND