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scores on an exam follow an approximately normal distribution with a mean of 76.4 and a standard deviation of 6.1 points. what is the minimum score you would need to be in the top 7%?

User Brosig
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To find the minimum score needed to be in the top 7%, we need to find the score that corresponds to the 93rd percentile, since the top 7% is the complement of the bottom 93%.

Using a standard normal distribution table or a calculator, we can find the z-score that corresponds to the 93rd percentile, which is approximately 1.44. This means that a score of 1.44 standard deviations above the mean corresponds to the 93rd percentile.

To find the actual score, we can use the formula:

z = (x - μ) / σ

where z is the z-score, x is the actual score, μ is the mean, and σ is the standard deviation. Solving for x, we get:

x = z * σ + μ

= 1.44 * 6.1 + 76.4

= 85.084

So, the minimum score needed to be in the top 7% is approximately 85.084 points.

User Paul Legato
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