Question

There are 9 chocolate bars in a bag of Halloween candy. The bag is dropped and 5 of the chocolate bars break. You take one random chocolate bar out, eat it and take another out. What is the probability that neither of these were broken?

Answer 1

it's below because

Explanation:

1/6 !!!!!!!!!!!!!!

Answer 2

Below

Explanation:

4 out of 9 are not broken first bar not broken chance is then 4/9

now there are 8 bars left and 3 are not broken so for the second bar thee is a 3/8 chance of not being broken

4/9 * 3/8 = 12/72 = 1/6