161k views
0 votes
If f(x)=3x^2+1 and g(x)=1-x, what is the value of (f-g)(2)?

User Zorzi
by
7.8k points

1 Answer

5 votes

Answer:

14

Explanation:

To find the value of (f-g)(2), we first need to compute the function (f-g), which is defined as the difference between f(x) and g(x), and then evaluate it at x=2.

So, (f-g)(x) = f(x) - g(x)

Substituting the given functions, we get:

(f-g)(x) = (3x^2 + 1) - (1-x)

(f-g)(x) = 3x^2 + x

Now, to find (f-g)(2), we substitute x=2 into the expression we just obtained:

(f-g)(2) = 3(2)^2 + 2

(f-g)(2) = 3(4) + 2

(f-g)(2) = 12 + 2

(f-g)(2) = 14

Therefore, the value of (f-g)(2) is [14.]

User Mevaka
by
7.5k points