Question

A 24n force causes a 2.0 kg mass to accelerate at 8.0m s^(-2) along a horizontal surface. the coefficient of dynamic friction is

Answer 1

Step-by-step explanation:

Let
`F_(R)` be the frictional force.

`F_(net) = F_(applied)-F_(R)`

2*8=24-
`F_(R)`

`F_(R)=24-16=8N`

`F_(g)=mg = 2*10 = 20N`

Coefficient of friction =
`(F_(R))/(F_(g))`

=8/20=2/5=0.4

The coefficient of friction = 0.4