Question

ABCD is a kite, So AC - DB and DE=EB Calculate the length of \overline{AC} AC to the nearest tenth of a centimeter.

Answer 1

AC=9CM

Explanation:

Since ABCD is a kite, we know that the two diagonals, AC and BD, intersect at right angles and that the two pairs of adjacent sides are congruent. Therefore, we have:

AC = BD and AB = BC = CD = DA

We also know that DE = EB, which means that triangle ADE is congruent to triangle BEC (by the side-side-side congruence rule), so we have:

AD = BC and AE = EC

AD=5cm and DC=4cm

Combining these equations, we have:

AC = AD + DC

AC=5cm+4cm=9cm