(i) 61/2000
(ii) 9/2
(iii) 261/400
Total no. of drivers = 2000
(i) exactly 3 accidents (18-29 years of age)
[ P(E)= no. of favourable outcomes/total no.of Outcomes]
P(E) = 61/2000
(ii) one or more accidents in a year (30-50 years of age )
= 125 +60 + 22 + 18
= 225
P( E) = 225/ 2000
= 9/2
(iii) having no accidents in one year
= 440 +505 +360
= 1305
P(E) = 1305/2000
=261/400
hope it helps
- Creativexcolours