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How do I graph these parametric equations on the interval (pi/2 , 3pi/2)x(θ) = 3 cos θy(θ) = 6 sin θ

User Jaroslaw Pawlak
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1 Answer

18 votes
18 votes

Given:


x(\theta)=3cos\theta\text{ and }y(\theta)=6sin\theta.

Required:

We have to draw the graphs of the given function.

Step-by-step explanation:

To draw the graph of the given functions proceeds as follows:

We know how to draw the graphs of sine and cosine functions. The given functions are multiples of sine and cosine.


x((\pi)/(2))=3cos((\pi)/(2))=3*0=0
x(\pi)=3cos(\pi)=3*-1=-3
x((3\pi)/(2))=3cos((3\pi)/(2))=3*0=0

Hence the graph of the function is

Similarly,


y((\pi)/(2))=6sin((\pi)/(2))=6*1=6
y(\pi)=6sin(\pi)=6*0=0
y((3\pi)/(2))=6sin((3\pi)/(2))=6*-1=-6.

Hence the graph of the function is

Final answer:

Hence the final answer is the two graph above. That is

And

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User Rune
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2.8k points