Question

In the decomposition of aqueous sodium hydroxide, how many moles of sodium hydroxide are needed to produce 30.0 moles of liquid water? (30.0 moles NaOH) ​2NaOH +h2 → 2Na+2h2o

Answer 1

Step-by-step explanation:

Consider the stoichiometry of the reaction, which is the ratio of reactant particles to product particles in the reaction. So in this reaction, the stoichiometry is:

2 : 1 : 2 : 2

Therefore, if you have 30 moles of water, than you have 30 moles of sodium hydroxide, 15 moles (30÷2) of hydrogen gas, and 30 moles of sodium.