Question

A sample of greenhouse gas, methane (CH4) at a pressure of 121.59 kPa, a volume of 31 liters, and a temperature of 360.15 K. How many moles (n) of gas and grams (g) of gas are in the sample?

Answer 1

Answer: 1.26 mol and 20.16g

Step-by-step explanation:

use ideal gas law

PV = nRT

121.59 x 31 = n x 8.314 x 360.15

n = (121.59 x 31)/(8.314 x 360.15)

n = 1.26 mol

x MM CH4 = 20.16g