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Percent yield quiz

1LIOH+1KCI1LICI + 1KOH
1.a) I began this reaction with 22 grams of LIOH. What is my theoretical yield of Li
22 Lia
percent yield =
actual yle
theoretical
b) I actually produced 8 grams of lithium chloride. What is my percent yield?
X 100
Com
Lanth

User Hallidave
by
7.9k points

1 Answer

3 votes

Answer:

a. 68.54 g

b. 11.67%

Step-by-step explanation:

The balanced chemical equation is:

1 LIOH + 1 KCI → 1 LICI + 1 KOH

a) The molar mass of LIOH is 23.95 g/mol. So, the number of moles of LIOH used is:

22 g / 23.95 g/mol = 0.920 mol

From the balanced chemical equation, we see that 1 mole of LIOH produces 1 mole of LICI. Therefore, the theoretical yield of LICI is 0.920 mol.

The molar mass of LICI is 74.55 g/mol. So, the theoretical yield of LICI in grams is:

0.920 mol × 74.55 g/mol = 68.54 g

Therefore, the theoretical yield of LiCl is 68.54 g.

b) The actual yield of LiCl is given as 8 grams.

The percent yield is given by the formula:

percent yield = (actual yield / theoretical yield) × 100%

Substituting the actual and theoretical yields, we get:

percent yield = (8 g / 68.54 g) × 100% = 11.67%

Therefore, the percent yield of LiCl is 11.67%.

User Mayank Gupta
by
7.3k points