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Paul opens a saving account and he deposits 150 per month. assume that he does not withdraw money or make any additional deposits.after 6 months there is 1,250 in his saving account

1) write an equation that represents the total amount of money paul deposits into his aacount (point slope form)

2) after how many months will paul have 2000 in his account?

point slope form formula: y-y=m(x-x)

1 Answer

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Answer: it will take Paul 11 months to have $2,000 in his account, assuming he does not withdraw any money or make any additional deposits.

Explanation:

Let x be the number of months that Paul has deposited money into his account. The total amount of money he deposits can be represented by the equation y = 150x, where y is the total amount of money in his account after x months.

To find the value of y after 6 months, we can substitute x = 6 into the equation:

y = 150(6) = 900

However, we know that the actual amount of money in Paul's account after 6 months is 1,250. This means that he must have earned interest on his deposits.

To account for the interest, we can add a constant term to the equation, representing the amount of interest earned. Let's call this constant term b. Then the equation becomes:

y = 150x + b

We know that when x = 6, y = 1,250. We can use this information to solve for b:

1,250 = 150(6) + b

b = 1,250 - 900

b = 350

So the equation that represents the total amount of money Paul deposits into his account is:

y = 150x + 350 (in point slope form, this is y - 350 = 150(x - 0)).

To find the number of months it will take for Paul to have $2,000 in his account, we can set y = 2,000 in the equation and solve for x:

2,000 = 150x + 350

1,650 = 150x

x = 11

Therefore, it will take Paul 11 months to have $2,000 in his account, assuming he does not withdraw any money or make any additional deposits.

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