Answer:
1. We are told that the medication decays by half each week. So, after one week, the amount of medication remaining is half of the original dose:
f(1) = (1/2) × &mL; = ½ &mL;
After two weeks, the amount of medication remaining is half of what was left after one week:
f(2) = (1/2) × ½ &mL; = ¼ &mL;
After three weeks, the amount of medication remaining is half of what was left after two weeks:
f(3) = (1/2) × ¼ &mL; = ⅛ &mL;
2. We are told that the medication decays by half each week. To find the amount of medication remaining one day after it is administered, we need to find the amount of medication that decays in one day. There are 7 days in a week, so the medication decays by a factor of ½ each &frac17; of a week. Therefore, the amount of medication remaining after one day is:
f(1/7) = ½ × &mL; = ½ &mL;
3. f(2) represents the amount of medication remaining in the dog's bloodstream two weeks after it is administered. We can plug w = 2 into the function f to find this amount, which is ¼ &mL.