Question

A 1-kg plastic block is neutrally buoyant when submerged in water with a density of 1 g/cm3. If the same block is placed, such that it is completely submerged, in a container of oil with a density of 0.8 g/cm3, find the acceleration of the block.

Answer 1

-2 m/s

Step-by-step explanation:

The computation of the acceleration of the block is as follows:

The volume of the block is

V = 1kg ÷ 1,000 kg/m^3 = 1 ÷ 1,000 m^3

Now at the time of submerging in the oil

Net force is

`m_g - F_B = m * (-a)\\\\m_g - v* S_(oil) * g = -ma\\\\a = ((v)/(m) * S_(oil) - 1) g\\\\= ((1)/(1000) * 0.8 * 1000 -1 ) * 10\\\\`

= -2 m/s