Answer:
here are 2.50 x 10^23 formula units in 32.4 g of aluminum hydroxide.
Step-by-step explanation:
The molar mass of aluminum hydroxide (Al(OH)3) is 78.0 g/mol.
To determine the number of formula units in 32.4 g of aluminum hydroxide, we first need to calculate the number of moles of aluminum hydroxide in 32.4 g:
moles of Al(OH)3 = mass / molar mass
moles of Al(OH)3 = 32.4 g / 78.0 g/mol
moles of Al(OH)3 = 0.415 mol
Next, we use Avogadro's number to convert the number of moles to the number of formula units:
number of formula units = moles of Al(OH)3 x Avogadro's number
number of formula units = 0.415 mol x 6.022 x 10^23/mol
number of formula units = 2.50 x 10^23 formula units
Therefore, there are 2.50 x 10^23 formula units in 32.4 g of aluminum hydroxide.