Question

3. A object of mass 0.25 kg moving to the right with a speed of20 m/s hits a wall and bounces back to the left with a speed of5 m/s. Calculate the change in its momentum. (1 point)A. O-2.205 kg m/sB. O-6.25 kg m/sC. O-10.07 kg m/sD. O-11.864 kg m/sE. O-8.237 kg m/s

Answer 1

B. -6.25 kg* m/s

Explanation:

Given:

Mass of car (m) = 0.25 kg

Speed of the car before the collision (v1) = 20 m/s

Speed of the car after the collision (v2) = - 5 m/s

Then we calculate the change of momentum as follows:

`\begin{gathered} p=m\Delta v \\ \\ \text{ we replacing} \\ \\ p=0.25\cdot\left(\left(-5\right)-20\right) \\ \\ p=-6.25\text{ kg*m/s} \end{gathered}`

The correct answer is B. -6.25 kg* m/s